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5b^2-9b-20=0
a = 5; b = -9; c = -20;
Δ = b2-4ac
Δ = -92-4·5·(-20)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{481}}{2*5}=\frac{9-\sqrt{481}}{10} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{481}}{2*5}=\frac{9+\sqrt{481}}{10} $
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